Hello-
I'm working on customizing a glockenspiel design, making the bars wider (1-1/4" or maybe even 1-1/2"), and thicker... 3/8". The bars will also have to be longer than the original design offered here.
I need to figure out how to create a new bar length graduation so that all the nodes will line up right on the frame.
Someone has told me that if I just "invent" the length of the shortest bar (Call it "S"),
and "invent" the length of the longest bar ("L"),
I can subtract the shortest bar from the longest bar and divide it by the number of bars ("N")
and the results will equal the amount ("A")
between what each bar length should be so the nodes will line up. So, to look a little like algebra it would be:
("L" minus "S") divided by "N" equals "A"
OR:
20"-10" divided by 20 equals a half inch.
(these numbers are just to make the example easy for me)
But yet, I think I may be missing something here. Maybe "N" should not actually equal the number of bars... but the sum total of all the widths of bars next to each other (either "white" or "black") plus the sum total of all those spaces in between those bars.
So... am I on the right track? What am I missing?
Thanks!